Let `n_(1)` and `n_(2)` moles of two different ideal gases be mixed. If adiabatic coeefiecient of the two gases are `gamma_(1)` and `gamma_(2)` respectively, then adiabatic coefficient `gamma` of the mixture is given through the relation

Using two different containers A and B, the coefficients of apparent expansion of a liquid are found to be gamma_(1) " and " gamma_(2) respectively. If the coefficient of linear expansion of the material A is alpha , find that of the material B.

When 1 mole of a monatomic gas is mixed with 3 moles of a diatomic gas, the value of adiabatic exponent gamma for the mixture is

The coefficient of apparent expansion of a liquid for two different vessels A and B are gamma_(1) " and " gamma_(2) respectively. If the coefficient of linear expansion of the material of the vessel A is alpha , then the coefficient of linear expansion of the material of the vessel B will be

Two diatomic gases are mixed in mole ratio 1:2. Find the value of adiabatic exponent for this mixture of gases.

The degree of freedom of mixture of two ideal gases having moles n_1 and n,_2 and degree of freedom f_1 and f_2 respectively, is

The coefficient of apparent expansion of a liquid when determined using two different vessle A and B are gamma_(1) and gamma_(2,) respectily. If the coefficient of linerar expansion of vesel A is alpha. Find the coefficient of linear expension of the vessel B.

The coefficient of apparent expansion of a liquid when determined using two different vessle A and B are gamma_(1) and gamma_(2,) respectily. If the coefficient of linerar expansion of vesel A is alpha. Find the coefficient of linear expension of the vessel B.

The coefficient of apparent expansion of a liquid when determined using two different vessle A and B are gamma_(1) and gamma_(2,) respectily. If the coefficient of linerar expansion of vesel A is alpha. Find the coefficient of linear expension of the vessel B.

Two ideal monoatomic and diatomic gases are mixed with one another to form an ideal gas mixture. The equation of the adiabatic process of the mixture is PV^(gamma)= constant, where gamma=(11)/(7) If n_(1) and n_(2) are the number of moles of the monoatomic and diatomic gases in the mixture respectively, find the ratio (n_(1))/(n_(2))