" (i) "y=2x^(2)-1" at "x=1

If y=2x^(2)-1 then (1)/(x^(2))+(1)/(2x^(4))+(1)/(3x^(6))+…infty equals to

y=x^(2)+1, y=2x-2, x=-1 , x=2

If y=(x^(2)+x+1)/(x^(2)-x+1)," then "(x^(2)-x+1)^(2)y_(1)=

The solution of the differential equation (x^(2)+1)(dy)/(dx)+(y^(2)+1)=0 is y=2+x^(2)by=(1+x)/(1-x)c*y=x(x-1)d.y=(1-x)/(1+x)

The area of the region bounded by y^(2)=2x+1 and x-y-1=0 is