[" The position vector of the foot of the "],[" perpendicular from "(1,-2,-3)" to the line "],[bar(r)=i+j+lambda(2i+j+k))_(" iS ")]

The position vector of the foot of theperpendicular from (1,-2,-3) to the line bar(r)=bar(i)+bar(j)+lambda(2bar(i)+bar(j)+bar(k)) is

If a=6hat(i)+7hat(j)+7hat(k), b=3hat(i)+2hat(j)-2hat(k), P(1, 2, 3) Q. The position vector of L, the foot of the perpendicular from P on the line r=a+lambdab is

If a=6hat(i)+7hat(j)+7hat(k), b=3hat(i)+2hat(j)-2hat(k), P(1, 2, 3) Q. The position vector of L, the foot of the perpendicular from P on the line r=a+lambdab is

If a=6hat(i)+7hat(j)+7hat(k), b=3hat(i)+2hat(j)-2hat(k), P(1, 2, 3) Q. The position vector of L, the foot of the perpendicular from P on the line r=a+lambdab is

If a=6hat(i)+7hat(j)+7hat(k), b=3hat(i)+2hat(j)-2hat(k), P(1, 2, 3) Q. The position vector of L, the foot of the perpendicular from P on the line r=a+lambdab is

vec(a)=6hat(i)+7hat(j)+7hat(k),vec(b)=3hat(i)+2hat(j)-2hat(k),P(1,2,3) The position vector of L, the foot of the perpendicular from P on the line vec(r)=vec(a)+lamdavec(b) is -

Find the position vector of the foot of perpendicular and the perpendicular distance from the point P with position vector 2hat i+3hat j+4hat k to the plane vec r*(2hat i+hat j+3hat k)-26=0. Also find image of P in the plane.

From a point A with position vector p(i+j+k) , AB and AC are drawn perpendicular to the lines r=k+lambda(i+j)" and "r=-k+mu(i-j) respectively. A value of p is equal to

Find the position vector of the centroid of the tetrahedron formed by the points 2bar(i)-bar(j)-3bar(k), 4bar(i)+bar(j)+3bar(k), 3bar(i)+2bar(j)-bar(k), bar(i)+4bar(j)+2bar(k) .