A block of mass 10 kg is kept on a fixed rough `(mu=0.8)` inclined plane of angle of inclination `30^(@)`. The frictional force acting on the block is

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A block of mass 10 kg is released on rough incline plane. Block start descending with acceleration 2m//s^(2) . Kinetic friction force acting on block is (take g=10m//s^(2) )

A body of mass m is kept on a rough fixed inclined plane of angle of inclination theta=30^(@) . It remains stationary. Then magnitude of force acting on the body by the inclined plane is equal to :

A body of mass m is kept on a rough fixed inclined plane of angle of inclination theta=30^(@) . It remains stationary. Then magnitude of force acting on the body by the inclined plane is equal to :

A block of mass 3 kg is at rest on a rough inclined plane with angle of inclination 30^@ with horizontal. If mu_s = 0.7, then the frictional force is

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m is at rest on a rough inclined plane of angle of inclination theta . If coefficient of friction between the block and the inclined plane is mu , then the minimum value of force along the plane required to move the block on the plane is

A block of mass m=2kg is resting on a rough inclined plane of inclination of 30^(@) as shown in figure. The coefficient of friction between the block and the plane is mu=0.5 . What minimum force F should be applied perpendicular to the plane on the block, so that blocks does not slip on the plane? (g=10m//s^(2))