An electron (charge `q=1.6xx10^(-19)C)` in the potentiometer wire experiences a force of `2.4xx10^(-19)`N. The length of the potentiometer wire is 6 m. The e.m.f. of the battery connected across the wire is

An electron in the potentiometer wire experiences a force of 2.4 xx 10^-19 N . The length of the potentiometer wire is 4 m. The emf of the battery connected across the wire is :

An electron in potentiometer experiences a force 2.4xx10^(-19)N . The length of potentiometer wire is 6m. The emf of the battery connected across the wire is (electronic charge =1.6xx10^(-19)C )

An electron in potentiometer experiences a force 2.4xx10^(-19)N . The length of potentiometer wire is 6m. The emf of the battery connected across the wire is (electronic charge =1.6xx10^(-19)C )

An electron in potentiometer experiences a force 2.4xx10^(-19)N . The length of potentiometer wire is 6m. The emf of the battery connected across the wire is (electronic charge =1.6xx10^(-19)C )

In figure AB is a potentiometer wire of length 10 m and resistance 1Omega . The balancing length for 2V potential drop is 18 m. The e.m.f. of the battery E is

In order to determine the internal resistance of a primary cell by means of potentiometer the emf of the battery connected across the ends of the potentiometer wire should be

If the electronic charge e=1.6xx10^(-19)C and the specific charge e/m off electron is 1.76xx10^(11)C(kg)^(-1) then calculate the mass m of the electron.

The balancing length for a cell in a potentiometer experiment is 45 cm. In the balanced condition, the current through the potentiometer wire is 2 A. If the total length of the potentiometer wire is 1 m and its total resistance is 60Omega , the emf of the cell is (in Volts) _________.