Let `alpha = (lambda-2) a + b` and `beta =(4lambda -2)a + 3b` be two given vectors where vectors a and b are non-collinear. The value of `lambda` for which vectors `alpha` and `beta` are collinear, is.

Let veca=(lambda-2)veca+vecb and vecbeta=(4lambda-2)veca+3vecb be two given vectors where vectors veca and vecb are non-collinear. The value of |lambda| for which vectors vecalpha and vec beta are collinear, is ________.

If a and b are non-collinear vectors, then the value of lambda for which " "u=(lambda+2)a+b and " "v=(1+4lambda)a-2b are collinear is

If vec a and vec b are non-collinear vectors,then the value of x for which vectors vec alpha=(x-2)vec a+vec b and vec beta=(3+2x)vec a-2vec b are collinear,is given by

If vec a and vec b are non-collinear vectors,find the value of x for which the vectors vec alpha=(2x+1)vec a-vec b and vec beta=(x-2)vec a+vec b are collinear.

For what value of lambda , the vectors (lambda-2)veca+vecb and (4lambda-2)veca+3vecb are collinear

If vec(a) and vec(b) are non-collinear vectors find the value of x for which vectors vec(alpha)=(x-2)vec(a)+vec(b) and vec(beta)=(3+2x)vec(a)-2vec(b) are collinear.

The non zero vectors bar(a) and bar(b) are not collinear find the value of lambda and mu : if bar(a) + 3 bar(b) = 2 lambda bar(a) - mu bar(b)

Using vectors find the value of lambda such that the points (lambda,-10,3),(1,-1,3) and (3,5,3) are collinear