The normal at `(1,1)` to the circle `x^2 + y^2 - 4x + 6y -4=0` is

The equation of the normal at (1,2) to the circle x^(2)-y^(2)-4x-6y-12=0 is

The lngth of the tangent from the point (1, 1) to the circle x^2 + y^2 + 4x + 6y + 1 = 0 is

The normal to-be circle x^2 +y^2 - 4x + 6y -12=0 passes through the point

The point (2, -1) ________ the circle x^(2) + y^(2) - 4x + 6y + 8 = 0 .

The inverse of the point (1, 2) with respect to the circle x^(2) + y^(2) - 4x - 6y + 9 = 0 is

The inverse of the point (1, 2) with respect to the circle x^(2) + y^(2) - 4x - 6y + 9 = 0 is

Find the equation of the normal to the circle x^(2) + y^(2)- 4x-6y+11=0 at (3,2) . Also find the other point where the normal meets the circle.

Find the equation of the normal to the circle x^(2) +y^(2) -4x -6y +11 0 at (3,2) Also find the other where the normal meets the circles.

Find where the normal to the circle x^(2)+y^(2)-4x+6y+9=0 is parallel to x-axis.