For a potentiometer to function, the emf of the cell (`E`) in the primary circuit compared to the emf of the cell (`E^(1)`) in the secondary circuit should have a realtion

For the working of potentiometer, the emf of cell in the primary circuit (E) compared to the emf of the cell in the secondary circuit (E^(1)) is

If the emf of the cell in the primary circuit is doubled, with out changing the cell in the secondary circuit, the balancing length is

In an open circuit the emf of the cell is

Choose the correct statements from the following a) in potentiometer experiment balancing length represent the potential difference across the secondary cell b) the shunt resistance between the terminals of cell in the secondary circuit of potentiometer is increased, the balancing length increases c) in potentiometer experiment the e.m.f of the cell in the secondary circuit may be greater than the e.m.f of cell in the primary circuit d) potentiometer is used to measure thermo e.m.f. also

Define e.m.f of a cell. How can you compare the e.m.f of the cells using potentiometer.

The e.m.f. of two cells can be compared by

A student finds the balancing length to be .l. with a cell of constant emf in the secondary circuit. Another student connects the same cell in the secondary circuit of potentio meterof double the length but with a cell of half the emf in the primary circuit. The balancing length will be [cell in primary is ideal and no series resistance is present in primary circuit]

A student finds the balancing length to be .l. with a cell of constant emf in the secondary circuit. Another student connects the same cell in the secondary circuit of potentio meterof double the length but with a cell of half the emf in the primary circuit. The balancing length will be [cell in primary is ideal and no series resistance is present in primary circuit]