A wheel starting with angular velocity of 10 radian/sec acquires angular velocity of 100 radian/sec in 15 seconds. If moment of inertia is `10kg-m^(2)` , then applied torque (in newton-metre) is

A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/ sec^(2) ?

A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/ sec^(2) ?

The rotational analogue of force is moment of force, also called torque.A wheel starting form rest acquires an angular velocity of 10 rad/s in two seconds. The moment of inertia of the wheel is 0.4 kg m^2 . Calculate the torque acting on it.

A fly wheel is making 300 rpm. Its angular velocity in radian per second is .

Starting from rest the fly wheel of a motor attains an angular velocity of 60 rad//sec in 5 seconds. The angular acceleration obtained is

A wheel is at rest. Its angular velocity increases uniformly and becomes 80 radian per second after 5 second. The total angular displacement is :-

A wheel is at rest. Its angular velocity increases uniformly and becomes 80 radian per second after 5 second. The total angular displacement is :-

The torque needed to produce an angular acceleration of 18rad/ "sec"^2 in a body of moment of inertia 2.5kg- m^2 would be -

A wheel is rotating with angular velocity 2 rad/s. It is subjected to a uniform angular acceleration 2 rad/s2 then the angular velocity after 10s is