If `k in N` ,such that `log_2x+log_4x+log_8x=log_k x!=1` then the value of k is

if log_kx.log_5k = log_x5 , k!=1 , k>0 , then find the value of x

There exists a positive number k such that log_2x+ log_4x+ log_8x= log_kx , for all positive real no x. If k= a^(1/b) where (a,b) epsilon N, the smallest possible value of (a+b)= (c)

There exists a positive number k such that log_2x+ log_4x+ log_8x= log_kx , for all positive real no x. If k= a^(1/b) where (a,b) epsilon N, the smallest possible value of (a+b)= (C) 12 A) 75 (B) 65 (D) 63_

There exists a positive number k such that log_2x+ log_4x+ log_8x= log_kx , for all positive real no x. If k= a^(1/b) where (a,b) epsilon N, the smallest possible value of (a+b)=

If log_2 (log_8x)=log_8(log_2x), find the value of (log_2x)^2.

if log_(k)x.log_(5)k=log_(x)5,k!=1,k>0, then find the value of x

There exists a positive number k such that log_(2)x+log_(4)x+log_(8)x=log_(k)x, for all positive real no x.If k=a^((1)/(b)) where (a,b)varepsilon N, the smallest possible value of (a+b)=(C)12 A) 75 (B) 65 (D) 63_(-)

If log (3+ 4 + k) = log 3 + log 4 + log k, then the value of k is

If (log_(5) K) (log_(3) 5) (log_(k) x ) = k , then the value of x if k = 3 is