Without changing the direction of the axes, the origin is transferred to the point (2,3). Then the equation `x^(2)+y^(2)-4x-6y+9=0` changes to

When the origin is shifted to (2,3) then the original equation of x^(2)+y^(2)+4x+6y+12=0 is

Without rotating the original coordinate axes, to which point should origin be transferred,so that the equation x^(2)+y^(2)-4x+6y-7=0 is changed to an equation which contains no term of first degree?

Without rotating the original coordinate axes, to which point should origin be transferred, so that the equation x^2 + y^2-4x + 6y-7=0 is changed to an equation which contains no term of first degree?

Without rotating the original coordinate axes, to which point should origin be transferred, so that the equation x^2 + y^2-4x + 6y-7=0 is changed to an equation which contains no term of first degree?

If the axes are transferred to parallel axes through the point (1,-2), then the equation y^(2) -4x +4y+8=0 becomes -

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , then term containing linear powers are missing, then point (h, k) is

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , the term containing linear powers are missing, then point (h, k) is

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , the term containing linear powers are missing, then point (h, k) is

Without change of axes the origin is shifted to (h, k), then from the equation x^(2)+y^(2)-4x+6y-7=0 , then therm containing linear powers are missing, then point (h, k) is

The origin shifted to (-5,3) then the equation y^(2)-12x+6y+69=0 changes as y^(2)=4ax then a