There exist positive integers A, B and C with no common factors greater than 1, such that 1, such that `A log_(200) 5+ B log_(200) 2=C` The sum `A + B+ C` equals

Show that log_(b)a log_(c)b log_(a)c=1

How many pairs of positive integers (a,b) are there such that a and b have no-common factor greater than 1 and (a)/(b)+14(b)/(a) is aa integer:

If a , b , c are consecutive positive integers and (log(1+a c)=2K , then the value of K is (a) logb (b) loga (c) 2 (d) 1

If a , b , c are consecutive positive integers and (log(1+a c)=2K , then the value of K is logb (b) loga (c) 2 (d) 1

Let a, b, c be real numbers, each greater than 1, such that (2)/(3)log_(b)a +(3)/(5) log_(c )b +(5)/(2) log_(a) c =3 . If the value of b is 9, then the value of 'a' must be

Let a , b , c , d are positive integer such that log_(a)b=3//2 and log_(c)d=5//4 . If a-c=9 , then value of (b-d) is equal to

a , b , c are positive integers formaing an incresing G.P. and b-a is a perfect cube and log_(6)a+log_(6)b+log_(6)c=6 , then a+b+c=

a , b , c are positive integers formaing an incresing G.P. and b-a is a perfect cube and log_(6)a+log_(6)b+log_(6)c=6 , then a+b+c=

a , b , c are positive integers formaing an incresing G.P. and b-a is a perfect cube and log_(6)a+log_(6)b+log_(6)c=6 , then a+b+c=

a , b , c are positive integers formaing an incresing G.P. and b-a is a perfect cube and log_(6)a+log_(6)b+log_(6)c=6 , then a+b+c=