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{i^(21)-((1)/(i))^(46)}^(2)=...

`{i^(21)-((1)/(i))^(46)}^(2)=`

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If Sigma_(i=1)^(20) ((""^(20)C_(i-1))/(""^(20)C_(i)+""^(20)C_(i-1)))^(3)=(k)/(21) , then k equals

If Sigma_(i=1)^(20) ((""^(20)C_(i-1))/(""^(20)C_(i)+""^(20)C_(i-1)))^(3)=(k)/(21) , then k equals

If Sigma_(i=1)^(20) ((""^(20)C_(i-1))/(""^(20)C_(i)+""^(20)C_(i-1)))^(3)=(k)/(21) , then k equals

If Sigma_(i=1)^(20) ((""^(20)C_(i-1))/(""^(20)C_(i)+""^(20)C_(i-1)))^(3)=(k)/(21) , then k equals

sum_(n=1)^(20)[sin((2n pi)/(21))-i cos((2n pi)/(21))]=

If (1-i)x+(1+i)y=1-3i , then (x,y) is equal to (a) (2,-1) (b) (-2,1) (c) (-2,-1) (d) (2,1)

If (1-i)x+(1+i)y=1-3i , then (x,y) is equal to (a) (2,-1) (b) (-2,1) (c) (-2,-1) (d) (2,1)

If (1-i)x+(1+i)y=1-3i , then (x,y) is equal to (a) (2,-1) (b) (-2,1) (c) (-2,-1) (d) (2,1)

simplify : i^(n+100)+i^(n+50)+i^(n+48)+i^(n+46)