`{:(x - ky = 2),(3x + 2y =-5):}`

{:(2x - 4y = 3),(5x - ky = 7.5):}

{:(2x - 4y = 3),(5x - ky = 7.5):}

Find the value of k for which the following system of linear equations : 2x -ky = 1, 3x - 5y = 7 will have :- a unique solution .

Consider the lines give by L_1: x+3y -5=0, L_2:3x - ky-1=0, L_3: 5x +2y -12=0

Find k if lines 5x - ky- 7=0 and 2x + 3y + 5 =0 are mutually perpendicular.

For the following system of equations determine the value of k for which the given system of equations has a unique solution: x-ky=2,quad 3x+2y=-5

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.

If the lines 2x + y - 3 = 0 , 5x + ky - 3 = 0 " and " 3x - y - 2 = 0 are concurrent , find the value of k.