लिखाचित्र खींचे-
`x-2y=4`

Equation of line touching both parabolas y^(2)=4x and x^(2) = -32y is a) x+2y + 4 =0 b) 2x +y4 =0 c) x-2y-4 =0 d) x-2y+4 =0

The factors of x^2+4y^2+4y-4x y-2x-8 are (a) (x-2y-4)(x-2y+2) (b) (x-y+2)(x-4y-4) (c) (x+2y-4)(x+2y+2) (d) none of these

Solve for x and y : 3x-2y=4 and 6x-4y=8

Solve the following systems of equations : (i) x - 2y = 0 3x + 4y = 20 (ii) x + y = 2 2x + 2y = 4 (iii) 2x - y = 4 4x - 2y = 6

The factors of x^(2)+4y^(2)+4y-4xy-2x-8 are (a)(x-2y-4)(x-2y+2)(b)(x-y+2)(x-4y-4)(c)(x+2y-4)(x+2y+2) (d) none of these

Given that x^2 + y^2 =4 and x^2 + y^2 -4x -4y =-4 , then x + y =

Statement 1 : The equations of the straight lines joining the origin to the points of intersection of x^2+y^2-4x-2y=4 and x^2+y^2-2x-4y-4=0 is x-y=0 . Statement 2 : y+x=0 is the common chord of x^2+y^2-4x-2y=4 and x^2+y^2-2x-4y-4=0

Statement 1: The equations of the straight lines joining the origin to the points of intersection of x^(2)+y^(2)-4x-2y=4 and x^(2)+y^(2)-2x-4y-4=0 is x-y=0 . Statement 2: y+x=0 is the common chord of x^(2)+y^(2)-4x-2y=4 and x^(2)+y^(2)-2x-4y-4=0

Statement 1 : The equations of the straight lines joining the origin to the points of intersection of x^2+y^2-4x-2y=4 and x^2+y^2-2x-4y-4=0 is x-y=0 . Statement 2 : y+x=0 is the common chord of x^2+y^2-4x-2y=4 and x^2+y^2-2x-4y-4=0

Consider the following equation in x and y: (x-2y-1)^2 + (4x+3y-4)^2 + (x-2y-1)(4x+3y-4) =0 How many solutions to (x, y) with x, y real, does the equation have