In the given figure, `MN||BC and AM: MB=1:2`
Find `("area" (Delta AMN))/("area" (Delta ABC))`

In the given figure , DE //BC and AD : AB= 2 : 5 Find : ( " area of " Delta ADE) /( " area of " Delta ABC) ( ii) (" area of " Delta ABC)/( " area of trapezium DBCE" )

In the figure, MN |\| BC " and " AM : MB = 1 : 3, " then " (ar(triangle AMN))/(ar(triangle ABC)) = …………..

In the given figure, DE is parallel to the base BC of triangle ABC and AD: DB = 5: 4. Find the ratio : ("Area of "DeltaDEF)/("Area of"Delta BFC)

In the given figure, DE||BC . If DE=3 cm, BC=6 and ar (Delta ADE)=15 cm^(2) , find the area of Delta ABC .

In the figure , DE || BC and (AD)/(DB) = 3/5 , calculate the value of (i) ("area of " Delta ADE)/("area of " Delta ABC) (ii) ("area of trapezium BCED")/("area of " Delta ABC)

In Delta ABC, D, E, F are respectively the mid points of the sides AB, BC and AC. Find ratio of the area of Delta DEF and area of Delta ABC .

In the adjoning figure, D and E are the points on the sides AB and AC respectively of Delta ABC and area of Delta BCE = " area of " Delta BCD . Prove that DE ||BC

In the adjoning figure, D and E are the points on the sides AB and AC respectively of Delta ABC and area of Delta BCE = " area of " Delta BCD . Prove that DE ||BC

In the following figure G, is centroid of the triangles ABC. Prove that Area (Delta " AGB " )= (1)/(3) xx " Area " (Delta ABC)