[" 9.The circle of "Delta ABC" touches the sides "BC" ,"CA" and "AB" at "D,E" and "F" respectively,If "ABquad [3]],[=AC," prove that "BD=CD]

The incircle of an isosceles triangle ABC in which AB=AC , touches the sides BC, CA, and AB at D, E, and F respectively. Prove that BD=DC .

The incircle of an isosceles triangle ABC, in which AB = AC, touches the sides BC, CA and AB at D, E and F respectively . Prove that BD = DC.

The incircle of an isoceles triangle ABC, with AB=AC, touches the sides AB,BC and CA at D,E and F respecrively. Prove that E bisects BC.

The incircle of an isoceles triangle ABC, with AB=AC, touches the sides AB,BC and CA at D,E and F respecrively. Prove that E bisects BC.

Let s denote the semi-perimeter of DeltaABC where BC=a, CA=b , and AB=c . If a circle touches the sides BC, CA, and AB at D, E, and F respectively, prove that BD= s-b .

The incircle of an isosceles triangle ABC , with AB=AC , touches the sides AB , BC , CA at D,E and F respectively. Prove that E bisects BC .

In Fig.10.19 ,the incircle of ABC touches the sides BC,CA and AB at D,E and F respectively.Show that AF+BD+CE=AE+BF+CD=(1)/(2)(Perimeter of ABC) (FIGURE)

The incircle of a triangle ABC touches the sides AB, BC and CA at the points F, D and E resepectively. Prove that AF + BD + CE + DC + EA = 1/2 (Perimeter of triangle ABC)

In Fig. the incircle of △ABC, touches the sides BC, CA and AB at D, E respectively. Show that : AF + BD + CE = AE + BF + CD = ½ (Perimeter of △ABC).