[" The freezing point of the solution containing "0.3gm" of acetic acid in "30gm" of benzene is "],[" lowered by "0.42^(@)C," then the van't Hoff factor is "(K_(f)" for benzene "=5.12Kkgmol^(-1))]

The freezing point of a solution containing 0.3 g of acetic acid in 30 g of benzene is lowered by 0.45^@c . Calculate the Vant's hoff factor (K_f for benzene = 5.12 K kg mol^-1) .

The freezing point of a solution containing 0.3 g of acetic acid in 30.0 g of benzene is lowered by 0.45^@ . Calculate the Van's Hoff factor. (K_f for benzene=5.12K kg mol^-1) .

The freezing point of a solution containing 0.3 g of acetic acid in 30 g of acetic acid in 30 g of benzene is lowerd by 0.54^(@) , Calculate Van't Hoff factor. (K_(f)" for benzene"= 5.12 " K kg mol"^(-1) ).

The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"

The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"

The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"

The freezing point of a solution containing 0*3 gms of acetic acid in 30 gms of benzene is lowered by 0*45 K . Calculate the van't Hoff factor. (At. wt. of C = 12, H = 1, 0 = 16, K_f " for benzene " = 5.12 " K kg mole"^(-1) ).