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5g of K(2)SO(4) are dissolved in 250mL o...

5g of `K_(2)SO_(4)` are dissolved in 250mL of solution. How many mL of this solution should be used so that 1.2 of `BaSO_(4)` may be precipated from `BaCl_(2)` solution?

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5 g of K_(2)SO_(4) was dissolved in 250 ml of solution. How many ml of this solution sholuld be used so that 2.33 g of BaSO_(4) may be precipitated from BaCl_(2) solution. K_(2)SO_(4)+BaCl_(2)rarrBaSO_(4)+2KCl

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Fill in the blanks. a. The equivalent weight of NaHCO_(3) is ……..and of SO_(2) is ……… b. 2 mol of 50% pure Ca(HCO_(3))_(2) on heating forms 1 mol of CO_(2) . The % yield of CO_(2) is …….. c. 5 g of K_(2) SO_(4) was dissolved in 250 mL of solution. The volume of this solution that should be used so that 1.2 g of BaSO_(4) be precipitated fromk BaCl_(2) is ....... (molecular mass of K_(2) SO_(4) = 174 and BaSO_(4) = 233 ) d. The residue obtained on strongly heating 2.76 g Ag_(2) CO_(3) is ........ [Ag_(2)CO_(3) overset(Delta)rarr Ag + CO_(2) + O_(2)] Atomic mass of Ag = 108

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