`DeltaH=30kJmol^(-1), DeltaS=75J//K//mol. "find boiling temperature at" 1atm: `

For the homogeneous reactions: xA+yBtolY+mZ DeltaH=-30kJ" "mol^(-1),DeltaS=-100JK^(-1)" "mol^(-1) At what temperature the reaction is at equilibrium?

For a reaction DeltaH=+29kJ" "mol^(-1),DeltaS=-35KJ^(-1)" "mol^(-1) at what temperature, the reaction will be spontaneous?

For the reaction at 298 K, 2A+BtoC DeltaH=400 kJ mol^(-1) and DeltaS=0.2 kJ K^(-1)mol^(-1). At what temperature will the reaction becomes spontaneous considering DeltaH and DeltaS to be constant over the temperature range?

Delta_(vap)H = 30 kJ mol^(-1) and Delta_(vap)S = 75Jmol^(-1)K^(-1) . Find the temperature of vapour, at 1 atm.

Delta_(vap)H = 30 kJ mol^(-1) and Delta_(vap)S = 75 mol^(-1)K^(-1) . Find the temperature of vapour, at 1 atm.

At 1 atm pressure, DeltaS=75JK^(-1)mol^(-1),DeltaH=30kJ" "mol^(-1) , the temperature of the reaction at equilibrium is

For a reaction M_(2)O_((g))to2M_((s))+1/2O_(2(g)) , DeltaH=30 k J mol^(-1) and DeltaS=0.07 k J mol^(-1) at 1 atm . Calculate up to which temperature, the reaction would not be spontaneous.

A+BtoC+D DeltaH=-10,000 J mol^(-1) DeltaS-33.3 J mol^(-1)K^(-1) At what temperature the reaction will occur spontaneous from left to right ?