9 balls are to be placed in 9 boxes and 5 of the balls cannot fit into 3 small boxes.the number of ways of arranging one ball in each of the boxes is

7balls (distinct) are to be placed in 7 boxes (distinct) and 4 of the balls can not fit into 2 small boxes.The number of ways of arranging one ball in each of the boxes is X .Let P be the probability of selected divisor in the list of divisors of X is in the Form of 4n+1 ,then find 6P (where n in N)

5 balls are to be placed into 3 boxes such that no box remains empty The number of ways in which this can be done.

There are 4 balls of different colour and 4 boxes of colours the same as those of the balls. Find the number of ways to put one ball in each box so that only two balls are in boxes with respect to their colour.

9articles are to be placed in 9 boxes one in each box.4 of them are too big for three of the boxes.The number of possible arrangements is.

5 balls of different colours are to be kept in 3 boxes of different sizes.Each box can hold all five balls.Number of ways in which the balls can be kept in the boxes so that no box remain empty is