Given that a photon of light of wavelength 10,000 angstrom has an energy equal to `1.23eV`. When light of wavelengths 5000 angstrom and intensity `I_(0)` falls on a photoelectric cell, the saturation current is `0.40 xx 10^(-6)` ampere and the stopping potential is 1.36 volt, then the work function is-

Given that a photon of light of wavelength 10,000Å has an energy equl to 1.23eV. When light of wavelength 5000Å and intensity I_(0) falls on a photoelectric cell and the saturation current is 0.40xx10^(-6) ampere and the stopping potential is 1.36 volt, then (i)what is the work function? (ii) If intensity of light is made 4I_(0) , what should be the saturation current and stopping potential?

Given that a photon of light of wavelength 10,000A has an energy equal to 1.23 eV. When light of wavelength 5000A and intenstiy I_0 falls on a photoelectric cell, the saturation current is 0.40xx10^(-6)A and the stopping potential is 1.36V, then the work function is

Given that a photon of light of wavelength 10,000A has an energy equal to 1.23 eV. When light of wavelength 5000A and intenstiy I_0 falls on a photoelectric cell, the saturation current is 0.40xx10^(-6)A and the stopping potential is 1.36V, then the work function is

A photon of wavelength 1000 Å has energy 12.3 eV . If light of wavelength 5000 Å , having intensity I, falls on a metal surface, the saturaion current is 0.40 mu A and the stopping potential is 1.36 V . The work function of metal is

For intensity I of a light of wavelength 5000 Å the photoelectron saturation current is 0.40 mu A and stopping potential is 1.36 V , the work function of metal is

For intensity I of a light of wavelength 5000 Å the photoelectron saturation current is 0.40 mu A and stopping potential is 1.36 V , the work function of metal is

Light of wavelength 5000 overset @A falls on a photosensitive plate with work function 1.9 eV. FInd maximum kinetic energy of photoelectron and stopping potential.