In triangle ABC, `a=3, b=4, c=2`. Point D and E trisect the side BC. If `angleDAE=theta`, then `cot^(2)theta` is divisible by :

In a triangle ABC, if a = 5, b=4 and c = 3, D and E are the points on BC such that BD = DE = EC. If DeltaDAE =theta, then tan theta =

In a triangle ABC, points D and E are taken on side BC such that BD=DE=EC. If angle ADE = angle AED=theta, then: (A)tan theta=3tan B(B)3tan theta=tan C

In a triangle ABC, points D and E are taken on side BC such that BD= DE= EC. If angle ADE = angle AED = theta , then: (A) tan theta = 3 tan B (B) 3 tan theta = tan C

In a triangle ABC, points D and E are taken on side BC such that BD= DE= EC. If angle ADE = angle AED = theta , then: (A) tan theta = 3 tan B (B) 3 tan theta = tan C (C) (6tan theta )/( tan^2 theta -9)= tanA (D) angleB = angle C

Let us consider a triangle ABC having BC=5 cm, CA=4cm, AB=3cm, D,E are points on BC such BD = DE= EC, angleCAE=theta , then: tan theta is equal to

Let us consider a triangle ABC having BC=5 cm, CA=4cm, AB=3cm, D,E are points on BC such BD = DE= EC, angleCAE=theta , then: AE^(2) is equal to

Let us consider a triangle ABC having BC=5 cm, CA=4cm, AB=3cm, D,E are points on BC such BD = DE= EC, angleCAE=theta , then: AD^(2) is equal to

Let us consider a triangle ABC having BC=5 cm, CA=4cm, AB=3cm, D,E are points on BC such BD = DE= EC, angleCAE=theta , then, AD^(2) is equal to

Let us consider a triangle ABC having BC=5 cm, CA=4cm, AB=3cm, D,E are points on BC such BD = DE= EC, angleCAE=theta , then: AE^(2) is equal to