The correct order for melting point and boiling point of IV group hydrides respectively
I) `CH_(4) lt SiH_(4) lt GeH_(4) lt SnH_(4)`
II) `CH_(4) gt SiH_(4) lt GeH_(4) lt SnH_(4)`
III) `SnH_(4) lt GeH_(4) lt SiH_(4) lt CH_(4)`
IV) `CH_(4) lt SiH_(4) gt GeH_(4) gt SnH_(4)`

Which among CH_(4), SiH_(4), GeH_(4) , and SnH_(4) is the most volatile?

Which among CH_(4),SiH_(4),GeH_(4) and SnH_(4) is the most volatile ?

The correct sequence of bond enthalpy of 'C-X' bond is : (1) CH_(3)-F gt CH_(3)-Cl gt CH_(3)-Br gt CH_(3)-I (2) CH_(3)-F lt CH_(3)-Cl gt CH_(3)-Br gt CH_(3)-I (3) CH_(3)-Cl gt CH_(3)-F gt CH_(3)-Br gt CH_(3)-I (4) CH_(3)-F lt CH_(3)-Cl lt CH_(3)-Br lt CH_(3)-I

The difference in properties of CH_(4) and SiH_(4) is due to :

Why is SiH_4 more reactive than CH_4 ?

The correct code for stability, of oxidation states for given cations is: (i) Pb^(2+) gt Pb^(4+) ,Tl^(+) lt Tl^(3+) (ii) Bi^(3+) lt Sb^(3+) , Sn^(3+) lt Sn^(4+) (iii) Pb^(3+) gt Pb^(4+),Bi^(3+) gt Bi^(3+) (iv) Tl^(3+) lt ln^(3+), Sn^(2+) gt Sn^(4+) (v) Sn^(2+) lt Pb^(2+) , Sn^(4+) gt Pb^(4+) (vi) Sn^(2+) lt Pb^(2+), Sn^(4+) lt Pb^(4+)

The correct code for stability, of oxidation states for given cations is: (i) Pb^(2+) gt Pb^(4+) ,Tl^(+) lt Tl^(3+) (ii) Bi^(3+) lt Sb^(3+) , Sn^(3+) lt Sn^(4+) (iii) Pb^(3+) gt Pb^(4+),Bi^(3+) gt Bi^(3+) (iv) Tl^(3+) lt ln^(3+), Sn^(2+) gt Sn^(4+) (v) Sn^(2+) lt Pb^(2+) , Sn^(4+) gt Pb^(4+) (vi) Sn^(2+) lt Pb^(2+), Sn^(4+) lt Pb^(4+)