Acceleration due to gravity ' g ' for a body of mass ' m ' on earth's surface is proportional to (Radius of earth= R , mass of earth= M

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

The earth’s radius is R and acceleration due to gravity as its surface is g. If a body of mass m is sent to a height of R/5 from the earth’s surface the PE increase (h = R/5) by:

The acceleration due to gravity'g' for objects on or near the surface of earth is related to the universal gravitational constant 'G' as ('M' is the mass of the earth and 'R' is its radius):