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The tension is the spring is...


The tension is the spring is

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The tension in the spring is.

A smooth table is placed horizontally and a spring of unstretched length i_(0) and force constank k has one end fixed to its center. To the other end of the spring is attached a mass m which is making n revolutions per second around the center. Show that the radius r of this unifrom circular motion is kl_(0)//(k-4 pi^(2)mn^(2)) and the tension T in the spring is 4pi^(2)mkl_(0)n^(2)//(k-4pi^(2)mn^(2))

A body of mass m= 20 g is attached to an elastic spring of length L=50 cm and spring constant k=2 Nm^(-1) . The syste is revolved in a horizontal plan with a frequency v=30 rev/min. Find the radius of the circular motion and the tension in the spring .

In the system shown in figure all surface are smooth, string in massless and inextensible. Find: (a) acceleration of the system (b) tensionin the string and (c ) tension in the spring if force constant of spring is k = 50 N/m (Take g = 10 m//s^(2) )

In an elevator a system is arranged as shown in figure. Initially elevator is at rest and the system is in equilibrium with middle spring unstretched. When the elevator accelerated upwards, it was found that for the new equilibrium position (with respect to lift), the further extension i the top spring is 1.5 times that of the further compression in the bottom spring, irrespective of the value of acceleration (a) Find the value of (m_1)/(m_2) in terms of spring constants for this happen. (b) if k_1=k_2=k_3=500(N)/(m) and m_1=2 kg and acceleration of the elevator is 2.5(m)/(s^2) , find the tension in the middle spring in the final equilibrium with respect to lift.

In an elevator a system is arranged as shown in figure. Initially elevator is at rest and the system is in equilibrium with middle spring unstretched. When the elevator accelerated upwards, it was found that for the new equilibrium position (with respect to lift), the further extension i the top spring is 1.5 times that of the further compression in the bottom spring, irrespective of the value of acceleration (a) Find the value of (m_1)/(m_2) in terms of spring constants for this happen. (b) if k_1=k_2=k_3=500(N)/(m) and m_1=2 kg and acceleration of the elevator is 2.5(m)/(s^2) , find the tension in the middle spring in the final equilibrium with respect to lift.