Determine a quadratic function (f) is defined by `f(x)=ax^2 +bx+c `. If f(0)=6,f(2)=11,f(-3)=6

Function f is defined by f(x) = 6 x - 3 find f(- 2).

Find the quadratic function defined by the equation : f(x) = ax^2 + bx +c if f(0) = 6,f(2) = 11 and f(-3) = 6

Find a quadratic function defined by the equation: f(x) = ax^2 + bx + c if f(1) =0,f(2)=-2and f(3)=-6

Find a quadratic function defined by the equation: f(x) = ax^2 + bx + c if f(0) = f(-1) = 0 and f(1)=2

Using determinants find the quadratic defined by f(x)= ax^(2) +bx+c, if f(1)=0, f(2)=-2 and f(3) = - 6.

Find a quadratic function defined by the equation : f(x)=ax^(2)+bx+c if (i) f(1)=0 , f(2)=-2 and f(3)=-6 (ii) f(0)=f(-1)=0 and f(1)=2

A function f(x) is defined as f(x) = -6x^(2) . What is f(-3) ?

Using matrix method, find the quadratic defined by f(x) = ax^(2) + bx + c if f(1) = 0, f(2) = -2 and f(3) = -6. Hence find the value of f(-1).

Function f is defined by f(x)=(3)/(2)x+c . If f(6)=1 , what is the value of f(c) ?

Find a function of the form f(x)=ax^(2)+bx+C . If it is known that f(0)=5, f(-1)=10, f(1)=6 .