An oil drop of radius r and density r is held stationary in a uniform vertically upwards electric field 'E'. If `p_(0)=(ltp)` is the density of air and e is quanta of charge, then the drop has–

An oil drop of radius r carrying a charge q remain stationary in the presence of electric field of intensity E. If the density of oil rho , then

An oil drop of mass m and charge +q is balanced in vaccum by a uniform electric field of intensity E . the direction of this field should be

An oil drop of mass m fall through air with a terminal velocity in the presence of upward electric field of intensity E . the drop carries a charge +q . R is the viscous drag force and f is the buoyancy force . Them for the motion of the drop.

An oil drop of radiuss 2mm with density 3(g/(cm^3)) is held stationary under a constant vec(E) = 3.35 xx 10^5 V/m in the milikan's drop experiment. What is number of excess electron that oil drop will possess (g=9.81)m/s^2

An oil drop of 10 excess electron is held stationary under a consatnt electric field of 3.6xx10^(4)NC^(-1) in Millikan's oil drop experiment. The density of oil is 1.26gcm^(-3) . Radius of the oil drop is (Take, g=9.8ms^(-2), e=1.6xx10^(-19)C )

An oil drop of 10 excess electron is held stationary under a consatnt electric field of 3.6xx10^(4)NC^(-1) in Millikan's oil drop experiment. The density of oil is 1.26gcm^(-3) . Radius of the oil drop is (Take, g=9.8ms^(-2), e=1.6xx10^(-19)C )

A sphere of charge of radius R has uniform volume charge density. The electric field due to the sphere of charge at a point