Let `f(x)=min{x,(x-2)^2}`for `x>=0then`

Let f(x)=min{x,(x-2)^(2)} for x>=0 then

Let f(x)=min{x,x^(2)}, for every x in R Then

Let f(x)=min{x,x^2} , for every x in R . Then

Let f(x)=min{4x+1,x+2,-2x+4}. then the maximum value of f(x) is

Let f(x)=min{|x+2|,|x|,|x-2|} then the value of the integral int_-2^2 f(x)dx is

Let f(x) = {{:(min{x, x^(2)}, x >= 0),(max{2x, x^(2)-1}, x (A) f(x) is continuous at x=0 (B) f(x) is differentiable at x=1 (C) f(x) is not differentiable at exactly three point (D) f(x) is every where continuous

Let f(x)=Min {x^(2)+1,x+1} for 0 <= x <= 2 .If A is the area bounded by y=f(x) , the x -axis in the interval [0,2] then find the integral part of A

Let f(x) ={|x|for 0< |x| , 2 for x=0