`4(x+y)(3a-b)+6(x+y)(2b-3a)`

Factorize each of the following algebraic expressions: 6x(2x-y)7y(2x-y)2r(y-x)+s(x-y)7a(2x-3)+3b(2x-3)9a(6a-5b)-12a^(2)(6a-5b)

Factorize: (y-x)a+(x-y)b9(z-2b)^(2)+6(2b-a)(x-2y)^(2)-4x+8y2a+6b-3(a+3b)^(2)

Factorize by suitable grouping: 4(a+b)(3x-y)+6(a+b)(2y-3x)

Factorize each of the following algebraic expressions: (1) (x-y)^2+(x-y) (2) 6(a+2b)-4(a+2b)^2 (3) a(x-y)+2b(y-x)+c(x-y)^2 (4) -4\ (x-2y)^2+8(x-2y)

The factors of (12 x - 8y) (a - 2b) + ( 6b - 2a) ( 3x - 2y) are :

Factorize: (a) (y-x)a+(x-y)b (b) 9(a-2b)^2+6(2b-a) (c) (x-2y)^2-4x+8y (d) 2a+6b-3(a+3b)^2

If (a)/(x-1) + (4b)/(y-2b) + (9c)/(z-3c)= 6-a find (ax)/(x-1) + (2y)/(y-2b) + (3z)/(z-3c) = ?

Factorize: 4(x+y)^(2)-28y(x+y)+49y^(2)(2a+3b)^(2)+2(2a+3b)(2a-3b)+(2a-3b)^(2)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

If (x+y)^3- (x-y)^3-6y (x^2-y^2)= k y^3, then k= (a)1 (b) 2 (c) 4 (d) 8