0.3 gm of platinichloride of an organic diacidic base left 0.09 gm of platinum on ignition. The molecular weight of the organic base is:

0.3 g of platinichloride of an organic diacidic base left 0.09 g of platinum on ignition. The molecular weight of the organic base is

0.3 g of platinichloride of an organic diacidic base left 0.09 g of platinum on ignition. The molecular weight of the organic base is

0.532 g of the platinitic chloric of a mono acid base left 0.195 g of plantiumas residue on ignition,.The equlivalnt weight of the base is

0.66 g of platinichloride of a monoacid base left 0-150 g of platinum. Calculate its molecular weight. (Pt = 195)

0.984 gm of the chloroplatinate of a diacid base gave 0.39 gm of platinum. Calculate the molecular mass of the base.

0.49 gm of chloroplatinate of a diacidic base gave on ingintion 0.195 gm of platinum. Calculate the molecular mass of the base.

0.984 g of a chloroplatinate salt of a diacid base on ignition gave 0.39 g of platinum. Find the molecular mass of the base.