Diazonium salt decomposes as
`C_(6)H_(5)N_(2)^(+)Cl^(-) rarr C_(6)H_(5)Cl + N_(2)`. At `0^(@)C`, the evolution of `N_(2)` becomes two times faster when the initial concentration of the salt is doubled. Therefore, it is

Diazonium salt decomposes as C_(6)H_(5)N_(2)^(o+)Cl^(ɵ) rarrC_(6)H_(5)Cl+N_(2) at 10^(@)C , the evolution of N_(2) becomes two first faster when the initial concentration of the salt is doubled. Thus, it is

Diazonium salt decomposes as C_(6)H_(5)N_(2)^(o+)Cl^(ɵ) rarrC_(6)H_(5)Cl+N_(2) at 10^(@)C , the evolution of N_(2) becomes two first faster when the initial concentration of the salt is doubled. Thus, it is

Diazonium salt decompose as : C_(6)H_(5)N_(2)CI^(-)rarrC_(6)H_(5)CI+N_(2) At 0^(@) C the evolution of N_(2) becomes two times faster when the initial concentration of the salt is doubled. Thus, it is

Diazonium salt decomposes as mathbf(C)_(6) (H)_(5) (~N)_(2)^+(Cl)- rarr (C)_(6) (H)_(5) (Cl)+(N)_(2^(*)) At 0^(circ) (C) the' evolution of (N)_(2) becoomes two times faster when the initial concentration of the salt is doubled. Therefore it is

C_(6)H_(5)N_(2)Cl + CuCN to C_(6)H_(5)CN + N_(2) + CuCl is

Benzenediazonium chloride dissociates as C_(6)H_(5)N_(2)^(+)Cl^(-)rarrC_(6)H_(5)Cl+N_(2) At 0^(@)C , if the concentration of diazonium salt is doubled , the rate of evolution of N_(2) is also doubled. Find the order of the reaction.