Of the ions `Zn^(2), Ni^(2 +)` and `Cr^(3 +)` [atomic number of `Zn = 30, Ni = 28, Cr = 24`]

Of the ions Zn^(2+),Ni^(2+) and Cr^(3+) (atomic number Zn=30,Ni=28,Cr=24):

Of the ions Zn^(2+),Ni^(2+) and Cr^(3+) (atomic number Zn=30,Ni=28,Cr=24):

Atomic number of Cr is 24, then Cr^(3+) will be :

Consier the following ions 1. Ni^(2+) 2. Co^(2+) 3. Cr^(2+) 4. Fe^(3+) Atomic number : Cr=24, Fe=26, Co=27, Ni=28. The correct sequence of increasing order of the number of unpaired electrons in these ions is

Consier the following ions 1. Ni^(2+) 2. Co^(2+) 3. Cr^(2+) 4. Fe^(3+) Atomic number : Cr=24, Fe=26, Co=27, Ni=28. The correct sequence of increasing order of the number of unpaired electrons in these ions is

Write the electronic configuration of Cu^(+) and Cr^(2+) ions (atomic number of Cu, and Cr are 29 and 24 respectively).

Which of the following is an inner orbital complex as well as diamagnetic in behaviour [Atomic numbers Zn = 30, Cr = 24, Co = 27, Ni = 28.]

Which of the following is an inner orbital complex as well as diamagnetic in behaviour [Atomic numbers Zn = 30, Cr = 24, Co = 27, Ni = 28.]

Consider the following ions: 1. Ni^((2+)) 2. Co^((2+)) 3. Cr^((2+)) 4. Fe^((3+)) (Atomic number : Cr: 24 , Fe=26, Co=27 and Ni=28 The correct sequence of increasing numbr of unpaired elecrons in these ions is 1,2,3,4 ; 4,2,3,1 ; 1,3,2,4 ; 3,4,2,1