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The ratio of area of any triangle PQR in...

The ratio of area of any triangle PQR inscribed in an ellipse `x^2/a^2+y^2/b^2=1` and that of triangle formed by the corresponding points on the auxilliary circle is `b/a`.

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The ratio of any triangle PQR inscribed in an ellipse x^2/a^2+y^2/b^2=1 and that of triangle formed by the corresponding points on the auxilliary circle is b/a .

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The ratio of any triangle PQR inscribed in an ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and that of triangle formed by the corresponding points on the auxilliary circle is (b)/(a) .

The ratio of the area of triangle inscribed in ellipse x^2/a^2+y^2/b^2=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then, find the eccentricity of the ellipse.

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The ratio of the area of triangle inscribed in ellipse x^2/a^2+y^2/b^2=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then, find the eccentricity of the ellipse. (A) 1/2 (B) sqrt3/2 (C) 1/sqrt2 (D) 1/sqrt3

The ratio of the area of triangle inscribed in ellipse x^2/a^2+y^2/b^2=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then, find the eccentricity of the ellipse. (A) 1/2 (B) sqrt3/2 (C) 1/sqrt2 (D) 1/sqrt3

The ratio of the area of triangle inscribed in ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 to that of triangle formed by the corresponding points on the auxiliary circle is 0.5. Then,find the eccentricity of the ellipse.(A) (1)/(2) (B) (sqrt(3))/(2) (C) (1)/(sqrt(2))(D)(1)/(sqrt(3))

Show that the area of a triangle inscribed in an ellipse bears a constant ratio to the area of the triangle formed by joining points on the auxiliary circle correspoinding to the vertices of the first triangle.