On heating `KCIO_(3)` we get :

On heating KVlO_(3) we get:

1.5 g of oxygen is produced by heating KCIO_(3) . How much KCI is produced in the reaction? 2KCIO_(3)(s)rarr 2KCl_(s)+3O_(2)(g)

Balance the equation , KCIO_(3) to KCI +O_(2)

2.00g of a mixture of NaHCO_(3) and KCIO_(3) present in the mixture is :

Calculate the volume of O_(2) at STP liberated by heating 12.25 g of KCIO_(3) . (At. Wt. of K=39, Cl=35.5, O=16 u)

When KClO_3 is heated we get