When a metallic surface is illuminated with monochromatic light of wavelength `lambda`, the stopping potential is `5 V_0` . When the same surface is illuminated with light of wavelength `3lambda`, the stopping potential is `V_0`. If work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with light of wavelength 3lambda , the stopping potential is V_0 . Then the work function of the metallic surface is:

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with light of wavelength 3lambda , the stopping potential is V_0 . Then the work function of the metallic surface is:

When a metallic surface is illuminated with monochromatic light of wavelength lambda ,the stopping potential is 5V_(0) .When the same surface is illuminated with light of wavelength 3 lambda ,the stopping potential is V_(0) .The work function of the metallic surface is (hc)/(n lambda) .Find n ?

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with the light of wavelength 3lambda , the stopping potential is V_0 . Then, the work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength lambda , the stopping potential is 5 V_0 . When the same surface is illuminated with the light of wavelength 3lambda , the stopping potential is V_0 . Then, the work function of the metallic surface is

When a metallic surface is illuminated with monochromatic light of wavelength X, the stopping potential is 5Vq. When the same surface is illuminated with light of wavelength 3X, the stopping potential is Then the work function of the metallic surface is

When a certain metalic surface is illuminated with monochromatic light of wavelength lamda the stopping potential is V_0 When the same surface is illuminated with light of wavelength 2lambda , the stopping potential frac(V_0)(4) ./ If the velocity of light in air is C, then find threshold frequency. Write down de Brogile hypotesis.

When a metallic surface is illuminated with radiation of wavelength lambda ,the stopping potential is V.If the same surface is illuminated with radiation of wavelength 2 lambda ,the metallic surface is

When a certain metallic surface is illuminated with mono chromatic light of wavelength lambda , the stopping potential for photoelectric current is 3V_(0) . When the same surface is illuminated with light of wavelength 2lambda the stopping potential is V_(0) . The threshold wavelength for this surface for photoelectric effect is.