The corrdinate of the points(s) on the graph of the function, `f(x)=(x^(3))/(3)-(5x^(2))/(2)+7x-4` where the tangent drawn cuts offintercepts from the coordinate axes which are equal in magnitude but opposite is sign, is

The coordinates of the point(s) on the graph of the function f(x)=(x^3)/x-(5x^2)/2+7x-4 , where the tangent drawn cuts off intercepts from the coordinate axes which are equal in magnitude but opposite in sign, are

The coordinates of the point(s) on the graph of the function f(x)=(x^3)/x-(5x^2)/2+7x-4 , where the tangent drawn cuts off intercepts from the coordinate axes which are equal in magnitude but opposite in sign, are (a) (2,8/3) (b) (3,7/2) (c) (1,5/6) (d) none of these

The coordinates of the point(s) on the graph of the function f(x)=(x^3)/3-(5x^2)/2+7x-4 , where the tangent drawn cuts off intercepts from the coordinate axes which are equal in magnitude but opposite in sign, are (a) (2,8/3) (b) (3,7/2) (c) (1,5/6) (d) none of these

Coordinates of the point on the graph of the function f(x) = (x-1)/(2 - x) where the tangent lines are perpendicular to the lines 8x + 2y = 1, are

If two roots of x ^(3) -ax ^(2) + bx -c =0 are equal in magnitude but opposite in sign. Then:

If two roots of x ^(3) -ax ^(2) + bx -c =0 are equal in magnitude but opposite in sign. Then:

Find the equation of the line which passes through the point (3, -5) and cuts off intercepts on the axes which are equal in magnitude but opposite in sign.

The abscissa of the point on the curve ay^(2)=x^(3) , the normal at which cuts off equal intercepts from the coordinate axes is

Find the equation of a line which passes through the point (5,1) and cuts, equal in magnitude but opposite in sign, intercepts on axes.

Find the equation of a line which passes through the point (5,1) and cuts, equal in magnitude but opposite in sign, intercepts on axes.