The product of perpendiculars from the focii upon any tangent of the ellipse `x^2/a^2+y^2/b^2=1` is `b^2`

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse x^2/a^2+y^2/b^2=1 is b^2

The product of the perpendiculars from the foci on any tengent to the ellipse x^2/a^2 + y^2/b^2 = 1 is

The product of the perpendiculars from the foci on any tangent to the ellipse x^(2)//a^(2)+y^(2)//b^(2)=1 is

Product of perpendiculars drawn from the foci upon any tangent to the ellipse 3x^(2)+4y^(2)=12 is

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is b^(2)

The product of the perpendiculars from the foci on any tangent to the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) = 1 is

The product of the perpendicular from two foci on any tangent to the hyperbola x^2/a^2-y^2/b^2=1 is (A) a^2 (B) (b/a)^2 (C) (a/b)^2 (D) b^2