The equation of displacement of particle performing S.H.M. is x = 0.25 sin (200 t). The maximum velocity is

The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then acceleration of the particle at 0.1 s is

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

The displacement of a particle executing SHM is given by y=0.25 sin(200t) cm . The maximum speed of the particle is

The displacement of a particle performing S.H.M. is x = 0.1 sin (5pit)+0.4cos(5pit)m . Then the speed of the particle at 0.1 s will be