Points on the curve `f(x)=(x)/(1-x^(2))`, where the tangent is inclined at an angle of `(pi)/(4)` to x-axis, are

Points on the curve f(x)=(x)/(1-x^(2)) where the tangent is inclined at an angle of (pi)/(4) to the x - axis are (0,0)(b)(sqrt(3),-(sqrt(3))/(2))(-2,(2)/(3))(d)(-sqrt(3),(sqrt(3))/(2))

Points on the curve f(x)=x/(1-x^2) where the tangent is inclined at an angle of pi/4 to the x-axis are (0,0) (b) (sqrt(3),-(sqrt(3))/2) (-2,2/3) (d) (-sqrt(3),(sqrt(3))/2)

Points on the curve f(x)=x/(1-x^2) where the tangent is inclined at an angle of pi/4 to the x-axis are (a)(0,0) (b) (sqrt(3),-(sqrt(3))/2) (-2,2/3) (d) (-sqrt(3),(sqrt(3))/2)

Points on the curve f(x)=x/(1-x^2) where the tangent is inclined at an angle of pi/4 to the x-axis are (a) (0,0) (b) (sqrt(3),-(sqrt(3))/2) (c) (-2,2/3) (d) (-sqrt(3),(sqrt(3))/2)

Points on the curve f(x)=x/(1-x^2) where the tangent is inclined at an angle of pi/4 to the x-axis are (0,0) (b) (sqrt(3),-(sqrt(3))/2) (-2,2/3) (d) (-sqrt(3),(sqrt(3))/2)

The coordinates of the point P on the curve x=a(theta+sintheta),y=a(1-costheta) where the tangent is inclined at angle pi/4 to the x-axis, are

Find the equation of the normal at the points on the curve y=(x)/(1-x^(2)) , where the tangent makes an angle 45^(@) with the axis of x.

The coordinates of the points on the curve x=a(theta+sin theta),y=a(1-cos theta), where tangent is inclined an angle (pi)/(4) to the x -axis are- (A) (a,a)(B)(a((pi)/(2)-1),a)(C)(a((pi)/(2)+1),a)(D)(a,a((pi)/(2)+1))