`2.0 g` of oleum is diluted with water. The solution was then neutralised by `432.5 mL of 0.1 N NaOH`. Select the correct statements:

0.5 gm of fuming H_(2)SO_(4) (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M NaOH solution. Calculate the percentage of free SO_(3) in the given sample. Give your answer excluding the decimal places.

0.5 gm of fuming H_(2)SO_(4) (Oleum) is diluted with water. This solution is completely neutralised by 26.7 ml of 0.4 M NaOH solution. Calculate the percentage of free SO_(3) in the given sample. Give your answer excluding the decimal places.

0.5 g of fuming sulphuric acid (H_2SO_4+SO_3) , called oleum, is diluted with water. Thus solution completely neutralised 26.7 " mL of " 0.4 M NaOH . Find the percentage of free SO_3 in the sample solution.

0.5 g of fuming sulphuric acid (H_2SO_4+SO_3) , called oleum, is diluted with water. Thus solution completely neutralised 26.7 " mL of " 0.4 M NaOH . Find the percentage of free SO_3 in the sample solution.

1 g of oleum sample is dilute with water. The solution required 54 mL of 0.4 N NaOH for complete neutralization. Find the percentage of free SO_(3) in the sample?