The angle of inclination of an inclined plane is `60^(@)`. Coefficient of friction between `10kg` body on it and its surface is `0.2, g= 10ms^(-2)`. The acceleration of the body down the plane in `ms^(-2)` is .

The coefficient of friction between a body and the surface of inclined plane at 45^@ is 0.5. If g=9.8m/s^2 The acceleration of the body downwards in m/s^2 is

The coefficient of friction between a body and the surface of an inclined plane at 45^(@) is 0.5. if g=9.8m//s^(2) , the acceleration of the body downwards I m//s^(2) is

The coefficient of friction between a body and the surface of an inclined plane at 45^(@) is 0.5. if g=9.8m//s^(2) , the acceleration of the body downwards I m//s^(2) is

The coefficient of friction between a body of mass 1kg and the surface of an inclined plane at 45^(@) is 0.5. if g=9.8m//s^(2) , the acceleration of the body downwards in m//s^(2) is

A block is lying on an inclined plane which makes 60^(@) with the horizontal. If coefficient of friction between block and plane is 0.25 and g=10m//s^2 , , then acceleration of the block when it moves along the plane will be

A block is lying on an inclined plane which makes an angle of 60^@ with the horizontal. If coefficient of friction between the block and the plane is 0.25 and g = 10 ms^(-2) , the acceleration of block when it is moves along the plane will be

block of mass 10 kg is kept on a rough inclined plane of angle 30° and coefficient of friction between the surfaces is u = 0.2. The acceleration of the block when a force F = 10 N is applied upward along the plane as shown in figure is (Take g = 10 ms^(-2) and sqrt3 = 1.7)