If the specific heat of lead is 0.03 cal/gm, then the thermal capacity of 500 gm of lead will be

A 25 g bullet travelling at 400 m//s passes through a thin iron wall and emerges at a speed of 250 m/s. If the bullet absorbs 50 percent of the heat generated, a. what will be the temperature rise of the bullet? B. If the ambient temperature is 20^(@)C will the bullet melt, and if so how much? Given that specific heat of head is 0.03 "cal"//gm^(@)C and latent heat of fusion of lead is 6000 cal/kg. It is also given that melting pont of lead is 320^(@)C .

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead= 327^@C , specific heat of lead = 0.03 cal //gm-^@C , latent heat of fusion of lead= 6 cal//gm,J=4.2 J //cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead= 327^@C , specific heat of lead = 0.03 calories //gm//^@C , latent jeat of fusion of lead= 6calories//gm,J=4.2 joules //calorie ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g.^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

A lead bullet just melts when stopped by an obstacle. Assuming that 25 per cent of the heat is absorbed by the obstacle, find the velocity of the bullet if its initial temperature is 27^@C . (Melting point of lead = 327^@C , specific heat of lead =0.03 cal//g-^@C , latent heat of fusion of lead =6 cal//g, J = 4.2 J//cal ).

Specific heat of mercury is 0.03 cal/ gm^(@) C. Its value in S.I is

The specific heat of an element is 0.214 cal/gm. The atomic weight is nearly