Debroglie wavelength of proton accelerated by an electric field at a potential difference `v` is

An electron of mass 'm' is accelerated by a potential difference V and the corresponding de-Broglie wavelength is lamda The de Broglie wavelength of a proton of mass M if it is accelerated by the same potential difference is.

If lamda_(0) is the De-Broglie wavelength for a proton accelerated through a potential difference of 100 V, De- Broglie wavelength for prop- particle accelerated through the same potential difference is

The de-Broglie wavelength associated with an electron accelerated through a potential difference V is lambda . What will be wavelength when accelerating potential is increased to 4V?

de-Broglie wavelength associated with an electron accelerated through a potential difference V is lambda . What will be its wavelength when the accelerating potential is increased to 4V?

The de Broglie wavelength associated with an electron accelerated through a potential difference V is lamda . What will be its wavelength when the accelerating potential is increased to 4 V?

The de Broglie wavelength of an electron accelerated by an electric field of V volt is given by:

De Broglie wavelength associated with an electron acclerated through a potential difference V is lambda . What will be its wavelength when the accelerating potential is increased to 4 V ?

de Broglie wavelength associated with an electron acclerated through a potential difference V is lambda . What will be its wavelength when the accelerating potential is increased to 4 V ?

The ratio of deBroglie wavelegth of a proton and an a-particle accelerated through the same potential difference is-