`5`g of steam at `100^(@)C` is mixed with `10`g of ice at `0^(@)C`. Choose correct alternative /s) :- (Given `s_("water") = 1"cal"//g ^(@)C, L_(F) = 80 cal//g , L_(V) = 540cal//g`)

The temperature of a body rises by 44^(@)C when a certain amount of heat is given to it . The same heat when supplied to 22 g of ice at -8^(@)C , raises its temperature by 16^(@)C . The water eqivalent of the body is [Given : s_(water) = 1"cal"//g^(@)C & L_(t) = 80 "cal" //g, s_("ice") = 0.5"cal"//g^(@)C ]

The temperature of a body rises by 44^(@)C when a certain amount of heat is given to it . The same heat when supplied to 22 g of ice at -8^(@)C , raises its temperature by 16^(@)C . The water eqivalent of the body is [Given : s_(water) = 1"cal"//g^(@)C & L_(t) = 80 "cal" //g, s_("ice") = 0.5"cal"//g^(@)C ]

The temperature of a body rises by 44^(@)C when a certain amount of heat is given to it . The same heat when supplied to 22 g of ice at -8^(@)C , raises its temperature by 16^(@)C . The water eqivalent of the body is [Given : s_(water) = 1"cal"//g^(@)C & L_(t) = 80 "cal" //g, s_("ice") = 0.5"cal"//g^(@)C ]

6 gm of steam at 100^@ C is mixed with 6 gm of ice at 0^@ C . Find the mass of steam left uncondensed. (L_(f)=80 cal//g,L_(v)= 540cal//g, S_(water) = 1cal//g-^(@) C) .

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

50 g of ice at 0^@C is mixed with 50 g of water at 80^@C . The final temperature of the mixture is (latent heat of fusion of ice =80 cal //g , s_(w) = 1 cal //g ^@C)

1 gram of ice at -10^@ C is converted to steam at 100^@ C the amount of heat required is (S_(ice) = 0.5 cal//g -^(@) C) (L_(v) = 536 cal//g & L_(f) = 80 cal//g,) .

10 g ice at 0^@C is converted into steam at 100^@C . Find total heat required . (L_f = 80 cal//g, S_w = 1cal//g-^@C, l_v = 540 cal//g)

0 g ice at 0^@C is converted into steam at 100^@C . Find total heat required . (L_f = 80 cal//g, S_w = 1cal//g-^@C, l_v = 540 cal//g)