The distance between the eletrodes of a conductivity cell is 0.98 cm and the cell constant is `0.5 cm^(-1)` . Calculate the cross-sectional area of electrode.

The distance between the electrodes of a conductivity cell is 0.98 cm and area of cross section of theeletrodeis 1.3cm^2 . Calculate the cell constant for the cell.

Distance between the electrodes of a conductivity cell is 1.75 cm, and the cross - sectional area of each electrode is 4cm^(2) . If the cell is filled wich 0.5(M) solution of an electrolyte, then the resistance of the cell becomes 25 ohm. Calculate the specific conductance of the solution.

The distance between two electrodes of a cell is 2.5 cm and area of each electrode is 5 cm2 the cell constant (in "cm"-^(1) ) is

Distance between the two electrodes of a conductivity cell is 1 cm, and the cross - sectional area of each electrode is 2cm^(2) . If the cell is filled with "50 g,L"^(-1) KCl solution, resistance of the cell appears to be 7.25 ohm. What is the molar conductivity of the solution?

0.05 M NaOH solution offers a resistance of 32 ohms in a conductivity cell at 298K. If the cell constant of the cell is 0.376 cm^(-1) , Calculate the molar conductance of NaOH solution.

0.05 "M" NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K. If the cell constant of the cell is 0.367 cm^(_1) calculate the molar conductivity of the NaOH solution.

0.05 M NaOH solution offered a resistance of 31.6 ohm in a conductivity cell at 298 K . If the area of the plates of the conductivity cell is 3.8 cm^(2) and distance between them is 1.4 cm , calculate the molar conductivity of the sodium hydroxide solution .