If V mL of a gaseous hydrocarbon after explosion with excess of oxygen showed a contraction of 2.5V mL and further contraction of 2V mL with potash. What will be the molecular formula of hydrocarbon?

If v mL of a gaseous hydrocarbon, after explosion with excess of oxygen, showed a contraction of 2.5 v mL and a further contraction of 2v mL with caustic potash, Find the formula of hydrocarbon.

If v mL of a gaseous hydrocarbon, after explosion with excess of oxygen, showed a contraction of 2.5 v mL and a further contraction of 2v mL with caustic potash, Find the formula of hydrocarbon.

20 mL of a gaseous hydrocarbon was exploded with 120 mL of oxygen . A contraction of 60 mL was observed and a further contraction of 60 mL took place when KOH was added. What is the formula of the hydrocarbon?

20 mL of a gaseous hydrocarbon was exploded with 120 mL of oxygen . A contraction of 60 mL was observed and a further contraction of 60 mL took place when KOH was added. What is the formula of the hydrocarbon?

6 mL of a gaseous hydrocarbon was exploded with excess of oxygen and the product cooled. A contraction of 9 mL was observed. A further contraction of 12 mL was observed on treatment with aqueous KOH. The formula of hydrocarbon is

20 mL of a gaseous hydrocarbon is exploded with excess oxygen in an eudiometer tube and the contraction in volume was 70 mL. Vapour density of the hydrocarbon is 29. Find its molecular formula