An electron jumps from `5th` orbit to `4th` orbit of hydrogen atom. Taking the Rydberg constant as `10^(7)` per meter. What will be the frequency of radiation emitted ?

An electron jumps from 3rd to 2nd orbit of hydrogen atom. Taking the Rydberg constant as 10^(7) m^(-1) , what will be the frequency of the radiation emitted?

An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom. Given the Rydberg's constant R = 10^(5) cm^(-1) . The frequency in Hz of the emitted radiation will be

An electron jumps from the 4th orbit to the 1st orbit of hydrogen atom. Given the Rydberg's constant R=10^(5) cm^(-1) . The frequency in Hz of the emitted radiation will be

An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom. Given the Rydberg's constant R = 10^5cm^(-1) the frequency in Hz of the emitted radiation will be

An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom. Given the Rydberg's constant R = 10^(5) cm^(-1) . The frequency in Hz of the emitted radiation will be

An electron jumps from the 4th orbit to the 2nd orbit of hydrogen atom.Given : the Rydberg's constant R=10^(5)cm^-1 .The frequency in Hz of the emitted radiation will be

An electron jumps from the 4^(th) orbit to the 2^(nd) orbit of hydrogen atom. Given the Rydberg's constant R=10^5cm^-1 . The frequency in Hz of the emitted radiation is

An electron jumps from the fourth orbit to the second orbit hydrogen atom. Given the Rydberg's constant R = 10^(7) cm^(-1) . The frequecny , in Hz , of the emitted radiation will be