The surface are frictionless, the ratio of `T_(1)` and `T_(2)` is

In the following figure, the pulley is massless and frictionless. The relation between T_(1), T_(2) and T_(3) will be :-

A ring takes time t_(1) in slipping down an inclined plane of length L, whereas it takes time t_(2) in rolling down the same plane. The ratio of t_(1) and t_(2) is -

A ring takes time t_(1) in slipping down an inclined plane of length L, whereas it takes time t_(2) in rolling down the same plane. The ratio of t_(1) and t_(2) is -

The whole set up shown in the figure is rotating with constant angular velocity omega on a horizontal frictionless table. The ratio of tensions (T_(1))/(T_(2)) is ("Given" (l_(2))/(l_(2)) = 2/1 )

For a first order reaction, the ratio of t_(1//2) to t_(3//4) is

Time period of pendulum on earth surface is T_(1) . Its time period at a height equal to radius of earth is T_(2) , then the ratio of T_(1) : T_(2) is

The time t_1 and t_2 are time period for 1/3 rd and 2/3 rd completion of two first order reactions If the half lives are in the ratio 10:3. then the ratio of t_1 and t_2 will be