Sea water is found to contain `5.85% NaCI` and`9.50% MgCI_(2)` by weight of solution. Calculate its normal boiling point assuming `80%` ionisation for `NaCI` and `50%` ionisation of `MgCI[K_(b)(H_(2)O) =0.51 kg mol^(-1)K]`

River water is found to contain 11.7% NaCl,9.5% "MgCl"_(2), and 8.4%. "NaHCO"_(3) , by weight of solution. Calculate its normal boiling point assuming 90% ionization of NaCl, 70% ionization of "MgCl"_(2) and 50% ionization of "NaHCO"_(3)("K"_("b") " for water" =0.52)

0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )

0.1 molal aqueous solution of an electrolyte AB_(3) is 90% ionised. The boiling point of the solution at 1 atm is ( K_(b(H_(2)O)) = 0.52 kg " mol"^(-1) )

An industrial waste water I found to contain 8.2% Na_(3)PO_(4) and 12% MgSO_(4) by mass in solution. If % ionisation of Na_(3)PO_(4) "and"MgSO_(4) Are 50 and 60 respectively then its normal boiliung point is [ K_(b)(H_(2)O) = 0.50 K kg "mol"^(-1) ] :

An industrial waste water I found to contain 8.2% Na_(3)PO_(4) and 12% MgSO_(4) by mass in solution. If % ionisation of Na_(3)PO_(4) "and"MgSO_(4) Are 50 and 60 respectively then its normal boiliung point is [ K_(b)(H_(2)O) = 0.50 K kg "mol"^(-1) ] :

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

2.0 molal aqueous solution of an electrolyte X_(2) Y_(3) is 75% ionised. The boiling point of the solution a 1 atm is ( K_(b(H_(2)O)) = 0.52K kg mol^(-1) )

3.0 molal aqueous solution of an electrolyte A_(2)B_(3) is 50% ionised. The boilng point of the solution at 1 atm is: [k_(b) (H_2O) = 0.52 K kg mol^(-1)]

3.0 molal aqueous solution of an electrolyte A_(2)B_(3) is 50% ionised. The boilng point of the solution at 1 atm is: [k_(b) (H_2O) = 0.52 K kg mol^(-1)]